Question

I a parallelogram shaped land , the cost of paving the land at the rate 50 paise per square metre is RS 150 and its base is 30m, find its height​

Answer 1

Answer:

10m

Explanation:

Given,

The cost of paving a parallel shaped land at the rate of Rs.0.50/m² is RS.150

$\rm \therefore \: Area \: of \: the \: land = \dfrac{Total \: cost}{Rate \: of \: paving}$

$= \dfrac{150}{0.50}$

$\rm = 300 {m}^{2}$

Therefore, area of the land is 300m²

Now,

Area of the parallel shaped land is given by,

$=b \times h$

Where,

• $b$(base) = 30m (given)
• $h$ denotes the height

Solving for $\boldsymbol h$

$\implies \: 300=bh$

$\implies \: 300=30h$

$\implies h = \dfrac{300}{30}$

$\implies h = \rm 10m$

Hence, height of the land is 10m

Answer 2

Given :

• Base of the parallelogram = 30 m
• Rate of paving = 50 paise
• Total cost = Rs.150

$\\ \rule{200pt}{3pt}$

To Find :

• Height of the parallelogram = ?

$\\ \rule{200pt}{3pt}$

Solution :

~ Formula Used :

$\large{\pink{\star}} \; {\underline{\overline{\boxed{\red{\sf{ Area{\small_{(Parallelogram)}} = Base \times Height }}}}}} \; {\pink{\star}}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Calculating the Area of land :

$\begin{gathered} \dashrightarrow {\qquad{\sf { Area{\small_{(Land)}} = \dfrac{Total \: Cost}{Rate} }}} \\ \end{gathered}$

$\begin{gathered} \dashrightarrow {\qquad{\sf { Area{\small_{(Land)}} = \dfrac{150}{50} }}} \\ \end{gathered} \; \; \; \; \bigg\lgroup {\purple{\sf{ Rs. \; 1 \; = 100 \; paise }}} \bigg\rgroup$

$\begin{gathered} \dashrightarrow {\qquad{\sf { Area{\small_{(Land)}} = \dfrac{150 \times 100}{50} }}} \\ \end{gathered}$

$\begin{gathered} \dashrightarrow {\qquad{\sf { Area{\small_{(Land)}} = \dfrac{15000}{50} }}} \\ \end{gathered}$

$\begin{gathered} \dashrightarrow {\qquad{\sf { Area{\small_{(Land)}} = \cancel\dfrac{15000}{50} }}} \\ \end{gathered}$

$\begin{gathered} \dashrightarrow {\orange{\qquad{\sf{ Area \; of \; land = 300 \; m² }}}} \\ \end{gathered}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Calculating the Height of parallelogram :

$\begin{gathered} \implies {\qquad{\sf { Area{\small_{(parallelogram)}} = Base \times Height }}} \\ \end{gathered}$

$\begin{gathered} \implies {\qquad{\sf { 300 = 30 \times Height }}} \\ \end{gathered}$

$\begin{gathered} \implies {\qquad{\sf { 300 = 30 \times Height }}} \\ \end{gathered}$

$\begin{gathered} \implies {\qquad{\sf { \dfrac{300}{30} = Height }}} \\ \end{gathered}$

$\begin{gathered} \implies {\qquad{\sf { \cancel\dfrac{300}{30} = Height }}} \\ \end{gathered}$

$\begin{gathered} \implies {\green{\qquad{\sf{ Height \; of \; parallelogram \; = 10 \; m }}}} \\ \end{gathered}$

$\\ \qquad{\rule{150pt}{1pt}}$

~ Therefore :

❛❛ Height of the parallelogram shaped land is 10 m . ❜❜

$\\ {\underline{\rule{300pt}{9pt}}}$