I a parallelogram shaped land , the cost of paving the land at the rate 50 paise per square metre is RS 150 and its base is 30m, find its height
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4
A
1
=A
2
Areaof∥(ABCD)=A
1
+A
2
=2A
1
NowΔABC
AB=39,BC=25,CA=56
S=
2
a+b+c
=
2
39+25+56
=60
Area=
S(s−a)(s−b)(s−c)
=
60(60−39)(60−25)(60−56)
=
60×21×35×4
=
3×5×4×3×7×7×5×4
=
3×3×5×5×4×4×7×7
=3×5×4×7
=840
Areaof∥ABCD=840×2
=1680
Lostofspeedingmud=1680×100
=168000
=Rs.1,68,000
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