Math, asked by rahulbenny0, 7 months ago

i a right ange triangle one angle measusres x where siin x=4/5 . whatis cos(90-x)?

Answers

Answered by pragati3652
0

Answer:

4\5

Step-by-step explanation:

cox(90-x)=sinx

sinx=4/5

Answered by itzcrazygirl70
1

cos (90 - x) = sin x = 4/5

cos (90 - x) = sin x = 4/5One way to show this is to use the formula cos(a - b) = cos a cos b + sin a sin b, where a=90 degrees and b = x degrees.

cos (90 - x) = sin x = 4/5One way to show this is to use the formula cos(a - b) = cos a cos b + sin a sin b, where a=90 degrees and b = x degrees.Another way is to recognize that the side adjacent to angle (90 - x) deg. is the same side that is opposite to the angle x deg. And so cos (90-x) = adjacent/hypotenuse = 4/5 = sin x = opposite/hypotenuse

Hope it helps u

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