Question

(i) A side of an isosceles right angled triangle is 7 cm. Find its hypotenuse.
(A) 102 cm (B) 72 cm (C) 162 cm (D) 82 cm​

Answer 1

Answer:

By pythagoras theorem

h^2 = 7^2 + 7^2

h^2 = 49 + 49

h^2 = 98

h = √98

Answer 2

The hypotenuse is $\sqrt{98}$.

Step-by-step explanation:

Given : A side of an isosceles right angled triangle is 7 cm.

To find : Its hypotenuse ?

Solution :

An isosceles right angled triangle follows the Pythagorean theorem which state that,

$H^2=P^2+B^2$

Where, H is the hypotenuse

P is the perpendicular

B is the base

Here, P=7 cm, B=7 cm

Substitute the values,

$H^2=7^2+7^2$

$H^2=49+49$

$H^2=98$

$H=\sqrt{98}$

Therefore, the hypotenuse is $\sqrt{98}$

#Learn more

Area of isosceles right triangle is 8 cm square find its hypotenuse​

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