i) A system does 820 J of work and at the same time absorbs 500 J of heat. Calculate the change in internal energy of the system.
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Answer:
Explanation:
given,
ΔW = -820 J ( if a system does work by itself then -ve sign is to be kept)
ΔQ = 500 J
We have find ΔU,
we have a formula
ΔU = ΔQ + ΔW
ΔU = 500 + (-820)
ΔU = -320
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