(i) A train covers a distance of 670 km in 6 h 5 min. If it covers the first 390 km of the
journey at 90 km/h, find its speed for the rest of the journey.
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Answer:
Time taken to cover 390km is
90km/h
390km
=4h20min
Remaining distance =670−390=280km
Remaining time =6h5min−4h20min=45min=0.75h
Speed =
0.75
280
=364kmph
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