Math, asked by trilochana2041, 19 days ago

(i) A triangle of sides 15 cm, 14 cm and 13 cm respectively.​

Answers

Answered by zainabfathima013
0

Solution

verified of triangle

a=13,b=14,c=15

Semi-perimeter s=

2

1

(a+b+c)=

2

1

(13+14+15)=21

Area, A =

s(s−a)(s−b)(s−c)

A=

21(21−13)(21−14)(21−15)

A=84 cm

2

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Step-by-step explanation:

Answered by ejazbano7
2

Step-by-step explanation:

ur question is:

Find the area of a triangle whose sides are 13 cm, 14 cm and 15 cm.

answer-

Given sides of triangle

a=13,b=14,c=15

Semi-perimeter s= 1/2 (a+b+c)= 1/2 (13+14+15)=21

Area, A = √s(s−a)(s−b)(s−c)

A=√ 21(21−13)(21−14)(21−15)

A=84 cm ^2

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