Question

I AABC, if angleA = 90° , AB = 100√3 mit and AC1000 then find it​

Answer 1

Step-by-step explanation:

AB=AC

AB=AC∠B=∠C [Angles opposite to equal sides are equal]

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o 100

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o 100 o

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o 100 o +2∠B=180

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o 100 o +2∠B=180 o

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o 100 o +2∠B=180 o

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o 100 o +2∠B=180 o ∠B=40

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o 100 o +2∠B=180 o ∠B=40 o

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o 100 o +2∠B=180 o ∠B=40 o

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o 100 o +2∠B=180 o ∠B=40 o Therefore,

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o 100 o +2∠B=180 o ∠B=40 o Therefore,∠B=∠C=40

AB=AC∠B=∠C [Angles opposite to equal sides are equal]In △ABC,∠A+∠B+∠C=180 o 100 o +2∠B=180 o ∠B=40 o Therefore,∠B=∠C=40 o