I already proved it. just for clearance
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Answered by
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Heya!
The answer is in the attachment provided.
Please refer to it once.
Hope this helps mate!
The answer is in the attachment provided.
Please refer to it once.
Hope this helps mate!
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KaifRahmani:
I also want to ask few question
Yep
ask?
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Answered by
0
sinA(1-2sin2A)/cosA(2cos-1)
tanA(1-2sin2A)/ {2(1-sin2A)-1}
tanA(1-2sin2A)/(2-2sin2A-1)
tanA(1-2sin2A)/(1-2sin2A)
tanA
tanA(1-2sin2A)/ {2(1-sin2A)-1}
tanA(1-2sin2A)/(2-2sin2A-1)
tanA(1-2sin2A)/(1-2sin2A)
tanA
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