Question

I am 10th class student ncert borad
please answer this question​

Answer 1

Answer:

59

Step-by-step explanation:

Area of Triangle = 1/2 × YZ × XS

118 = 1/2 × YZ × 4

59 = YZ

Answer 2

Solution :-

Given that :

• ∆XYZ = 118m²
• XS = 4m

Need to find :

• YZ

In the given triangle XS ⊥ YZ and we also given the area of triangle and height. We can use the formula of area of triangle and the base which is XS.

Formula :-

${\small{\underline{\boxed {\tt{\red{Area \: of \: triangle = \frac{1}{2} \times base \times perpendicular \: height}}}}}}$

Put the values we get,

$\sf:\longmapsto{118 = \frac{1}{2} \times base \times 4 } \\ \\ \sf:\longmapsto{118 = \frac{1}{ \cancel{2}} \times \cancel{4} \times base} \\ \\ \sf:\longmapsto{118 = 2 \times base} \: \: \: \: \: \: \: \: \\ \\\sf:\longmapsto{base = \cancel{\frac{118}{2} }} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ :\longmapsto { \boxed{ \bf{ \red{base = 59m}} }} \: \: \: \: \: \:$

Option [B] is answer

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