Math, asked by Vikram6888, 3 months ago

I am 3-digit number. My hundred digit is odd. My tens digit is more than 6. I am an even number. Who am I?

Answers

Answered by dhana232323
0

Answer:

Step-by-step explanation:

Given.. its an even number that means it has an even number in it's once place (2,4,6,8,0)

Given its hundreds digit is odd which means it can have 1 , 3 , 5 , 7 , 9 any of numbers these in 100th place.

Given its tens digit is more than 6 so it can have 7 , 8 , 9 , 0 any of these numbers in its place. hence by combining the above mentioned numbers we can get an even number as required by the question..

Answered by anyagounder
0

Answer:

592 is the answer to this riddle.

Step-by-step explanation:

it is the answer because under the circumstances it must follow all the rules for the number. You just have to make sure if:

- it is a 3 digit number

- it's hundred digit is odd ( which means it has to be 1, 3, 5, 7, or 9)

- it's tens digit is more than 6 ( so it has to be 7, 8, or 9)

- and that t is an even number ( so that means it has to end in 0, 2, 4, 6, or 8)

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