Math, asked by chiragmunjal4655, 20 days ago

I am a 2-digit number.
I am also the sum of the common factors of 8 and 48.
What number am I?

Answers

Answered by prajnalisarisa
3

Answer:

15

Step-by-step explanation:

Common factors of 8 and 48 are 1, 2, 4 and 8.

It is given that sum of the common factors of 8 and 48 is the 2 digit number.

So, 1+2+4+8=15

Answer is 15.

Answered by vinod04jangid
0

Answer:

15 is the number.

Step-by-step explanation:

Given :- The number is sum of all the common factors of 8 and 48.

To Find :- A two digit number which is the sum of common factors of 8 and 48.

Solution:-

First we need to find the factor of the numbers 8 and 48.

8 = 2 × 2 × 2

48 = 2×2×2×2×3

All the factors of 8 are 1, 2, 2 × 2 = 4 and 2 × 2 × 2 = 8.

The factors of 48 are 1, 2, 4, 8, 16, 6, 12, 24, 48.

Hence, the common factors of 8 and 48 are 1, 2, 4 and 8.

Now adding up all the common factors, we get

=  1+2+4+8

=  1 + 2 + 12

=  1 + 14

=  15

Therefore, 15 is the 2-digit number which is the sum of the common factors of 8 and 48.

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