Question

i am a 5 digit number my ones digit is 2 less than my ten thousands digit. my hundreds digit is 1 less than my ten thousands digit and my other digits are twice my ones digit. what numbers can i be?

Answer 1

Explanation:

98991 this is the answer

Answer 2

Answer:

The number is 44342.

Explanation:

Let us assume the 5 digit no. as ABCDE.

According to the situation,

$\begin{array}{l}{E=A-2} \\ {C=A-1} \\ {A=2 E} \\ {B=2 E} \\ {D=2 E}\end{array}$

So basically, $A=B=D$

Now, $A=2E$

(As we know that $E=A-2$)

So, $A=2(A-2)$

$A=2A-4$

$A=4$

Hence, $\mathrm{E}=4-2=2 ; \mathrm{C}=4-1=3 ; \mathrm{A}=2^{*} 2=4 ; \mathrm{B}=2^{*} 2=4 ; \mathrm{D}=2^{*} 2=4$

The answer becomes ABCDE $= 44342$.  

It is a 5 digit number

The one’s digit is 2 less than the ten thousand digit, i.e. $4-2=2$

The hundredth digit is one less than the ten thousand digit, i.e. $4-1=3.$

And it says that the other digits are of the same value and are 2 times the ones digit.

Becoming 44,342.