i am a digit number below 50 the sum of my digits is 13 and the product of my digits is 36 who am i
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Answered by
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Let the number be 10x+y.
Digits of number are x and y.
According to question,
x+y=13⇒x=13-y
and xy=36
Substituting the value of x,
(13-y)y=36
13y-y²=36
y²-13y+36=0 [Now, Factorising]
y²-9y-4y+36=0
y(y-9)-4(y-9)=0
(y-4)(y-9)=0
Now, y=4 or y=9
When y=4, x=13-y=13-4=9 and the number becomes 94.
When y=9, x=13-y=13-9=4 and the number becomes 49.
But, no. should be less than 50.
Therefore,
The number is 49 Ans
HOPING THAT IT WILL HELP YOU!!!
Digits of number are x and y.
According to question,
x+y=13⇒x=13-y
and xy=36
Substituting the value of x,
(13-y)y=36
13y-y²=36
y²-13y+36=0 [Now, Factorising]
y²-9y-4y+36=0
y(y-9)-4(y-9)=0
(y-4)(y-9)=0
Now, y=4 or y=9
When y=4, x=13-y=13-4=9 and the number becomes 94.
When y=9, x=13-y=13-9=4 and the number becomes 49.
But, no. should be less than 50.
Therefore,
The number is 49 Ans
HOPING THAT IT WILL HELP YOU!!!
Answered by
0
Answer:
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