I am a five-digit even number. I have 9 at my tens place. The digit at the ten thousands place is three less than the digit at the tens place. The digit at the hundreds place is half the value of the digit at the ten thousand place. The digit at the thousand place is double the digit at the ones place. Who am I? 68494 (2) 61392 (3) 64391 G (4 68394
Answers
Answer:
(4) 68394
Step-by-step explanation:
the digit at the thousand place is double the digit
at the ones place =(1)68494 (4)68394
the digit at the hundred place is half the value of the digit at the ten thousand place =(4)68394
The number is 68394.
Option (4) is correct.
Given:
- I am a five-digit even number.
- I have 9 at my tens place.
- The digit at the ten thousands place is three less than the digit at the tens place.
- The digit at the hundreds place is half the value of the digit at the ten thousand place.
- The digit at the thousand place is double the digit at the ones place.
To find:
- Who am I?
- (1) 68494
- (2) 61392
- (3) 64391
- (4) 68394
Solution:
Concept to be used:
Put the values according to the given statement.
Step 1:
Write the 5 digit number.
Let the number is EDCBA.
According to the place values from right to left these alphabets are arranged.
Step 2:
9 is at my tens place.
So,
B= 9
The digit at the ten thousands place is three less than the digit at the tens place.
So,
E= 9-3
E= 6
The digit at the hundreds place is half the value of the digit at the ten thousand place.
C=6/2
C= 3
The digit at the thousand place is double the digit at the ones place.
A<=> 2D
Step 3:
The number will be 6D39A.
From the options number will be 68394.
Only this satisfy the condition of thousands place and ones place.
Thus,
The number is 68394.
Option (4) is correct.
Learn more:
1) Find the digit which replaces @ in the given question
78*56-3@338=38818
https://brainly.in/question/11381607
2) which digit should replace in the number 46*368 so that it is divisible by 11
https://brainly.in/question/4418516