Math, asked by choukseyishita, 11 months ago

I am a number whose double is 40 greater than my half.

Answers

Answered by shubhrakumari
0

Answer:

80/3

Step-by-step explanation:

let the number be x .

Then,

2x =40+x/2

2x-x/2=40

(4x-x)/2=40

3x/2= 40

x=(40*2)/3

x=80/3

the required. number is 80/3

hope ,it will help you....

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