Question

I am a special quadrilateral in which all my vertex angles are equal but the adjacent sides are not equal. Who am I​

Answer 1

Answer:

Step-by-step explanation:

It is Rectangle.

In Rectangle all the vertex are equal.

Opposite sides are equal.

Diagonals bisect one another.

 Opposite angles are equal.

  Diagonals are equal.

Each of the angles is a right angle.

But the adjacent sides of the rectangle are different.

Answer 2

Given :- I am a special quadrilateral in which all my vertex angles are equal but the adjacent sides are not equal. Who am I ?

Answer :- Rectangle .

Explanation :-

• All four vertex angles of a rectangle equals to 90° .
• Opposite sides are equal in length and adjacent sides are not equal .

therefore, we can conclude that, Rectangle is right answer .

Note :-

• In square all 4 sides are equal and all 4 vertex angles are also equal .
• In Rhombus all 4 sides are equal and opposite angles are equal only .

Learn more :-

ABCD is a rhombus with A = 60° , BC = (3x+5)cm , CD =(6x-10)cm and AC =(3y-1)cm. Find

x and y.

please urgent please

n...

https://brainly.in/question/25624939

3.

In the fig, AB || CD,FIND x.(Hint:Prove that AOB-COD).

https://brainly.in/question/17942233