Question

I am a three digit number. My tens digit is five more than my ones digit. My hundreds digit is eight less than my tens digit. What number am I?​

Answer 1

sorry I am very busy I am going to listen class

make me as brilliant

Answer 2

Answer:

Step-by-step explanation:

To solve such a question we have to make some conditions and by applying these conditions according to the question

we can easily find our number.

Range of 3 digit number is from (100−999) and range of 2 digit number is (10−99).

Complete step by step solution:

Let the unit digit to be X then, according to the question x must be greater than equal to zero (as unit place of 100 is 0)

and it also must be less than or equal to nine (as the highest number in unit place can be equal to 9).

And this is also valid for tens digit so, according to the question the equation forms as X+5≤9 i.e.,X≤4.

For hundreds digit is eight less than X+5 so equation become X+5−8≥0 ⇒X−3≥0⇒X≥3 which implies that X greater than 3 and greater than or equal to 4. i.e., = [3,4].

And as given in the question

Let the unit digit to be 3and hence the tens digit become 8 and the hundreds digit become 0 and number forms as 083.

Let unit Let unit digit to be 4 and hence the tens digit become 9 and the hundreds digit become 1 and number forms as 194.

And therefore, the number is either 083 or 194 and we know that 083 is a two-digit number and therefore, our required number is 194.

Therefore, the three digit number is 194.