I am a three digited number.
My ten’s unders place is 5 more than my one’s digit.
My hundred’s digit is 8 lessthan my ten’s digit.
What number am I
Answers
Answer:
194
Step-by-step explanation:
Since the hundreds digit is eight less than the tens digit, the tens digit has to be 9. This is because 9 is the only positive integer less than 10 that is greater than 8, and thus the only one that will give a positive integer result when 8 is subtracted from it
We already know that the ones digit is 5 less than the tens digit, so it is 9–5=4. And the hundreds digit has to be 1. So the answer is 194.
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Given : a three digited number. ten’s unders place is 5 more than my one’s digit. hundred’s digit is 8 lessthan my ten’s digit.
To find : Number
Solution:
Let say number = ABC
Hundred's Digit = A
Ten's Digit = B
Unit's Digit = C
B = C + 5
A = B - 8 = C + 5 - 8 = C - 3
A can not be zero as its 3 digit numbers
=> C - 3 > 0
=> C > 3
B = C + 5
=> C + 5 < 10 ( ax maximum possible digit = 9)
=> C < 5
C > 3 & C < 5
3 < C < 5
=> only possible Value of C = 4
B = C + 5 = 4 + 5 = 9
A = B - 8 = 9 - 8 = 1
ABC = 194
194 is required three digited number
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