Question

I am an equilateral triangle my base is 3 more than twice of congruent sides .My perimeter is 35 then what the length of my base​

Answer 1

Given:

I am an equilateral triangle my base is 3 more than twice of congruent sides. My perimeter is 35

To find:

What the length of my base​?

Solution:

Let "x" be the length of each of the congruent sides of the triangle.

My base is 3 more than twice of congruent sides

So,

The length of its base = 2x + 3

The perimeter of the triangle = 35

We know,

$\boxed{\bold{Perimeter \:of\:a\:triangle = sum \:of\:all\:3 \:sides}}}$

Therefore, by using the above formula, we can form the equation as follows:

$x + x+ 2x+3 = 35$

$\implies 2x + 2x + 3 = 35$

$\implies 4x + 3 = 35$

$\implies 4x = 35 - 3$

$\implies 4x = 32$

$\implies \bold{x = 8}$

∴ $2x +3 = (2 \times 8) + 3 = 16 + 3 = \bold{19}$

Thus, the length of my base is → 19.

------------------------------------------------------------------------------------------

Also View:

the hypotenuse of a right triangle is 6M more than twice the shortest side. if the third side is 2 metres less than the hypotenuse finds the sides of a triangle.

brainly.in/question/7844515

The first side of a triangle is 2 cm longer than the second side the third side is 5cm shorter than the peace II side if the perimeter of the rectangle is 49 cm find the length of its side

brainly.in/question/5560586

The hypotenuse of a right-angled triangle is 1m less than twice the shortest side. if the third side is 1m more than the shortest side, find the sides of the triangle

brainly.in/question/3560716