Question

I am an even number between 70 and 80 . The sum of my digits is 13. I am

Answer 1

Answer:

The number is 76 as 7+6=13

Answer 2

The required number is 76.

Given:

A required number is an even number such that the sum of its digits is 13.

To Find:

The required number.

Solution:

Since the required number lies between 70 and 80, its tens place is occupied by 7. Let us assume that its unit place is 'y'.

⇒ The number = 70+y.

We are given that the sum of its digits = 13.

⇒ 7+y = 13

⇒ y = 13-7=6.

Hence, the number is = 70+y = 70+6 = 76.

∴ The required number is 76.

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