I am asking it again pleeez answer fast
Solve it
8 * 2^2x + 4 * 2^x+1 = 1 + 2^x
Anonymous:
Bro , I can answer it , but I have a confusion.
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Given expression is
8×2^2x + 4×2^x + 1 = 1 + 2x
Let 2x = t, we get 8t2+4t+1 = 1+t⇒8t2+4t = t⇒8t2+3t = 0⇒t(8t+3) = 0⇒t = 0 or t = −38⇒2x = 0 or 2x = −38
Now, 2x will always be greater than 0, that means, it will always be positive.Thus, both the final expressions do not lead to any solution.
8×2^2x + 4×2^x + 1 = 1 + 2x
Let 2x = t, we get 8t2+4t+1 = 1+t⇒8t2+4t = t⇒8t2+3t = 0⇒t(8t+3) = 0⇒t = 0 or t = −38⇒2x = 0 or 2x = −38
Now, 2x will always be greater than 0, that means, it will always be positive.Thus, both the final expressions do not lead to any solution.
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Hey !!
Q no. 1
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Solution is in this given pic !!
Hope it helps you
@Rajukumar111
Q no. 1
___________________________
Solution is in this given pic !!
Hope it helps you
@Rajukumar111
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