Math, asked by VaibhavClash, 1 year ago

I am asking it again pleeez answer fast

Solve it
8 * 2^2x + 4 * 2^x+1 = 1 + 2^x


Anonymous: Bro , I can answer it , but I have a confusion.
Anonymous: Is it ur q , 8 * 2^( 2 x ) + ( 4*2^x ) + 1 = 1 + ( 2^ x)
VaibhavClash: Yep
VaibhavClash: You r right
VaibhavClash: Its answer is -3 but I want to know steps
Anonymous: ok bro , I know it
Anonymous: Sorry , I can't .
Anonymous: Hey , check ur q once

Answers

Answered by yogiraj4
0
Given expression is

8×2^2x + 4×2^x + 1 = 1 + 2x
Let 2x = t, we get 8t2+4t+1 = 1+t⇒8t2+4t = t⇒8t2+3t = 0⇒t(8t+3) = 0⇒t = 0 or t = −38⇒2x = 0 or 2x = −38
Now, 2x will always be greater than 0, that  means, it will always be positive.Thus, both the final expressions do not lead to any solution.



Answered by TheLifeRacer
1
Hey !!

Q no. 1
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Solution is in this given pic !!

Hope it helps you

@Rajukumar111
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