I am asking it for the second time...please help
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This is not step by step but you can understand.
Hope this helps!!!
Hope this helps!!!
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It will help if you draw the diagram yourself following the given info :- • lets consider PQRS as a rectangle . let A , B, C and D be the mid points of PQ, RQ, RS and SP respectively.
• Join ABCD . Now we have to prove that ABCD formed is a ||gm.
Let's begin :-
• join PR . Now in the ∆PQR , since A and B are mid points of the two sides then , AB || PR and AB = 1/2 PR ( mid- point theorem )----( i )
Now in ∆PSR , again D and C are mid points of the two points , so , DC || PR and DC=1/2 PR ( mid point theorem ) ----( ii )
• comparing (i) and (ii) , we get AB=DC and AB || DC . Hence , ABCD is a parallelogram . Proved ;)
• Join ABCD . Now we have to prove that ABCD formed is a ||gm.
Let's begin :-
• join PR . Now in the ∆PQR , since A and B are mid points of the two sides then , AB || PR and AB = 1/2 PR ( mid- point theorem )----( i )
Now in ∆PSR , again D and C are mid points of the two points , so , DC || PR and DC=1/2 PR ( mid point theorem ) ----( ii )
• comparing (i) and (ii) , we get AB=DC and AB || DC . Hence , ABCD is a parallelogram . Proved ;)
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