Math, asked by hansi52, 7 months ago

i am four times as old as my daughter in 20 years time i shall be twice as old as her how old are we​

Answers

Answered by asahilthakur
2

Answer:

Let my daughter's present age be x.

My age = 4x

After 20 years,

My daughter's age = x + 20

My age = 4x + 20

According to Question,

2 (x + 20) = 4x + 20

2x + 40 = 4x + 20

40 - 20 = 4x - 2x

2x = 20

x = 10

Hence, my daughter's age = 10 years

My age = 4 × 10 = 40 years

Answered by leishangthoiba2
0

Answer:

let.

my daughter's present age be x.

and my age be 4x.

again,

my daughter's present age is x+20

and my age is 4x+20

by the question,

2(x+20)=4x+20.

2x+40=4x+20.

2x-4x=20-40.

-2x=-20.

x=-20/-2.

x=10

the present age of my daughter is 10 years.

my age is 10×4=40.

;40years

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