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What is the Value of Universal Constant of Gravitation if
Mass = 5.972 × 10^24 kg
Radius of the Planet is 6,371 kg
I know the Values and Formula g = GM/R^2

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Answer:

We know that tangent drawn from external point to a circle are equal

So AD=AF=x

Or BD=BE=y

And CF=CE=z

Now, AB=AD+DB=x+y=12 cm ...(1)

Or BC=BE+EC=y+z=8 cm ...(2)

And AC=AF+CF=x+z=10 cm ...(3)

Adding the above three equation, we get

2(x+y+z)=12+8+10=30 cm

Or x+y+z=15 cm

As per equation (1),

x+y=12 cm

Then, z=15−10=5 cm =CF

As per equation (3),

x+z=12 cm

Then, y=15−12=3 cm =BE

As per equation (2),

y+z=8 cm

Then, x=15−8=7 cm =AD
Why do people respond like this give me a better answer here

Answer 1

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Answer 2

Answer:

no u didn't did any mistakes in my question that I had asked.

Explanation:

thank you now I will mark you as brainliest now. but I can't, still someone can say me my answer then. Sorry. but if any one will, then I will mark you. Thank you very much.