I am having math exam pls answer .......
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∠TRS = ∠TQR + ∠QTR (Exterior angle of a triangle equals to the sum of the two opposite interior angles)
∠QTR = ∠TRS - ∠TQR (i)
Also,
∠SRP = ∠QPR + ∠PQR
2∠TRS = ∠QPR + 2∠TQR
∠QPR = 2∠TRS - 2∠TQR
 = ∠TRS - ∠TQR
From (i) and (ii), we get
∠QTR - ∠TQR = 
Hence, proved
∠QTR = ∠TRS - ∠TQR (i)
Also,
∠SRP = ∠QPR + ∠PQR
2∠TRS = ∠QPR + 2∠TQR
∠QPR = 2∠TRS - 2∠TQR
 = ∠TRS - ∠TQR
From (i) and (ii), we get
∠QTR - ∠TQR = 
Hence, proved
Anonymous:
hope this helps
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