Question

I am having my paper today please help me please plzz don't give the wrong answer​

Answer 1

Answer:

Step-by-step explanation:

1.=1/6

Answer 2

when 2 dice rolled the sample space will be :[(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)]=36

-'- n(s)=36

let n(e) be event for getting prime number on each dice.

-'- n(e)={(2,2)(2,3)(2,5)(3,2)(3,3)

(3,5)(5,2)(5,3)(5,5)}=9

let n(a) be event for getting total of 9 or 11

-'-n(a)={(6,3)(5,4)(4,5)(3,6)(6,5)

(5,6)}=6

1. The probability of getting a prime number on each dice :

p(e)=n(e)/n(s)

= 9/36=1/4

2. The probability of getting total 9 or 11:

p(e)=n(a)/n(s)

=6/36=1/6

hope this help you....