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Answers
Answer:
Given :
Dimensions of the cuboidal solid block = 30 cm × 40 cm × 50cm.
Force applied by block = 50 N
To Find :
The maximum pressure that will be exerted by the block on ground.
Solution :
Dimenions of the cuboidal solid block (in m) = 0.3 m × 0.4 m × 0.5 m.
Area of the first face,
A₁ = 0.3 × 0.4 = 0.12 m²
Area of the second face,
A₂ = 0.4 × 0.5 = 0.20 m²
Area of the third face
A₃= 0.5 × 0.3 = 0.15 m²
Out of the above three faces , A₁ is minimum. [Here the minimum value of area is considered to calculate the maximum pressure because P ∝ 1/A]
The relation between Pressure (P) , Force(F) and Area (A) is given by ,
\maltese \: {\large{\boxed{ \bf{Pressure= \dfrac{Force}{Area}}}}}✠
Pressure=
Area
Force
\begin{gathered} \\ : \implies \sf \: P = \dfrac{50 \: N}{0.12 \: {m}^{2} } \\ \end{gathered}
:⟹P=
0.12m
2
50N
\begin{gathered} \\ : \implies \boxed{ \bf{P = 416.66 \: N{m}^{ - 2} }} \: \dag \\ \\ \end{gathered}
:⟹
P=416.66Nm
−2
†
∴ The maximum pressure applied by the given cuboidal solid block is 416.6 N/m².