Question

i am more than forty. the sum of my digits is eight, my ones digit is one. what am i

Answer 1

Answer:

The required number is 71

Step-by-step explanation:

Concept used:

Any two digit number xy can be written as the sum of x tens and y ones

Let the two digit number be 10x+y

Given:

sum of digits = 8

⇒ x+y =8...................(1)

but ones digit is 1

⇒ y=1

put y=1 in (1) we get

x + 1 = 8

x = 7

Therefore, the required number is 7(10)+1=71

Answer 2

Answer: 71

Step-by-step explanation:

The question is very simple to answer.

From the question, it can be made out that the number will be above forty and as depicted in the question itself the sum of the digits will be eight (8).

Now, taking a rough guess of how many numbers above forty have a sum 8. We can say number 46, 53, 62, 71 and 80.

But the next hint clears the doubt as it says that the ones digit is 1. So, we simply get the answer 71.

Mathematical derivation isn't necessary according to me because i think it's a riddle or something.