Question

i am not solve this question so help me to solve this question​

Answer 1

Answer:

1.21

Step-by-step explanation:

To find--->

(1.331)⁻¹+(1.331)⁻²+.... +(1.331)⁻⁷

{-----------------------------------------------}²/³

(1.331)⁻²+(1.331)⁻³+.....+(1.331)⁻⁸

Solution--->

(1.331)⁻¹+(1.331)⁻² + ....+(1.331)⁻⁷

{-----------------------------------------------}²/³

(1.331)⁻²+(1.331)⁻³+...+(1.331)⁻⁸

Let 1.331 = x

x⁻¹ + x⁻² +...................+x⁻⁷

( ---------------------------------------------)²/³

x⁻² + x⁻³ + .................. + x⁻⁸

(x⁻¹ + x⁻² + ...............+x⁻⁷)

={--------------------------------------- }²/³

x⁻¹ ( x⁻¹ + x⁻² + .......+ x⁻⁷)

(x⁻¹ + x⁻² + ........+x⁻⁷ ) is cancel out from numerator and denominator

= ( 1 / x⁻¹ )²/³

We have a law of exponent

1 / a⁻ⁿ = aⁿ

Applying it here we get

= ( x )²/³

Putting x = 1.331 in it

= ( 1.331 )²/³

= (1.1 × 1.1 × 1.1 )²/³

= { (1.1)³ }²/³

We have a law of exponent

( aᵐ )ⁿ = aᵐⁿ

Applying it here we get

= (1.1 )³ ˣ ² /³

= ( 1.1 )²

= 1.1 × 1.1

= 1.21