Question

I am organising a party and I am trying to avoid any leftovers.
Samosas come in packets of 8.
Rasgollas come in packets of 12.
Packets of samosas and rasgollas cannot be split in the shop.
What is the fewest number of packets of samosas that I can buy so that each samosa has
a rasgolla?

Answer 1

Answer:

Answer is 4

Step-by-step explanation:

Answer 2

Given:

No. of samosas = 8

No. of rasgollas = 12

To find:

No. of packets of samosas required so that each samosa has a rasgolla.

Solution:

Here, we have samosas in packets of $8$ and rasgollas in packets of $12$. To determine the no. of packets of samosas required so that each samosa has a rasgolla, we find the HCF of $8$ and $12$.

Factors of $8$, $8=2*2*2$

Factors of $12$, $12=2*2*3$

To find the common factor, we check which all prime factors are common in both. Here, a pair of $2$ is present in both numbers, i.e., $4$ is common in both.

Thus, 4 packets of samosas have to be bought in order to have one samosa each with a rasgolla.

The fewest no. of packets of samosas that I can buy so that each samosa has a rasgolla is $4$.