Question

I am really in need of it please answer it correctly ​

Answer 1

Answer:2

a+b+c=0

(a+b)2=(-c)

a2+2ab+b2=(c)2

(a2+b2-c2)2=(-2ab)2

a4+b4+c4+2a2b2-2b2c2-2c2a2=4a2b2

a4+b4+c4+2a2b2-4a2b2-2b2c2-2c2a2=0

a4+b4+c4-2a2b2-2b2c2-2c2a2=0

a4+b4+c4=2a2b2+2b2c2+2c2a2

a4+b4+c4=2(a2b2+b2c2+c2a2)

substituting this value with a4+b4+c4/a2b2+b2c2+c2a2

We get,

2(a2b2+b2c2+c2a2)/a2b2+b2c2+c2a2=2

Hope it helps u..please mark my answer as brainliest