I am rectangle find value of x and y and peremeter and area
Answers
Answer:
the figure is a rectangle
=> opposite sides are equal
=>2x-y+13 = x-2y+20
=>2x-x+13-20= -2y+y
=>x-7= -y
=>x+y= 7 ----1
again smaller sides are opposite therefore equal
=> 3y=2x+6
=>2x-3y= -6 -----2
Solving 1 and 2 simultaneously
2(x+y=7)
2x-3y= -6
=> 3x+3y= 21
2x-3y= -6
=> 5x = 14
=> x= 14/5
and for y
=> x+y = 7
=> 14/5+y = 7
=> 5y+14 = 35
=> 5y = 21
=> y = 21/5
we get the value of x =
and value of y=
Now finding area and perimeter
=> 2x-y+13 = 2(14/5)- (21/5)+13. (putting values of x and y)
we get
2x -y +13 = 72/5
=> x-2y+20 = 72/5 (opposite sides are equal)
for another side
=>3y =3(21/5) ( putting value of y)
=>3y = 63/5
=> 2x +6 = 63/5 ( opposite sides are equal)
=> 63/5 ×72/5 = 907.2
=> 2×(63/5 +72/5 )
=> 54
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