Question

I am sending this question again and again. This is the third turn. This Question is not answered yet. If x = 1/ (2 - √3), then find the value of x^2 + 3x - 14

Answer 1

Step-by-step explanation:

$given \: it \: x = \frac{1}{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 + \sqrt{3} \\ then \: \: \: {x}^{2} + 3x - 14 \\ = {(2 + \sqrt{3} )}^{2} + 3(2 + \sqrt{3} ) - 14 \\ = 4 + 3 + 4 \sqrt{3} + 6 + 3 \sqrt{3} - 14 \\ = 13 - 14 + 7 \sqrt{3} \\ = 7 \sqrt{3} - 1 \\ \\ hope \: it \: will \: help \: you \:$