Question

I am stuck on these sums 1 part ii) and iv)​

Answer 1

Hey mate! here is your answer

(ii) (2x + 1) (3x - 2) = 6(x + 1) (x - 2)

=> 2x (3x - 2) +1 (3x - 2) = (6x + 6) (x - 2)

=> 6x^2 - 4x + 3x - 2 = 6x (x - 2) +6 (x - 2)

=> 6x^2 - x -2 = 6x^2 - 12x + 6x - 12

=> 6x^2 - x - 2 = 6x^2 - 6x - 12

=> 6x^2 - 6x^2 -x + 6x -2 + 12

=> -5x + 10

No, it is not a quadratic equation.

(iv) x - 3/x = 2

= x^2 - 3/x = 2

= x^2 - 3 = 2 × X

= x^2 - 3 = 2x

= X^2 - 2x - 3 = 0

Yes, it is a quadratic equation.

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Answer 2

Answer:

Refer to the attachment For ii and iv