Question

I am stuck on this plz answer ​

Answer 1

Answer:

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Answer 2

Answer:

2y^2 - y - 1

Step-by-step explanation:

Firstly, factorizing that equation :

       2y^3 + y^2 - 2y - 1

  ⇒ y^2( 2y + 1 ) - ( 2y + 1 )

  ⇒ ( 2y + 1 )( y^2 - 1 )

  ⇒ ( 2y + 1 )( y + 1 )( y - 1 )

Then,

     ( 2y^3 + y^2 - 2y - 1 ) / ( y + 1 )

⇒ ( 2y + 1 )( y - 1 )( y + 1 ) / ( y + 1 )

⇒ ( 2y + 1 )( y - 1 )

          Method 2 :

          2y^2 - y - 1            

y + 1 ) 2y^3 + y^2 - 2y - 1 (

         2y^3 + 2y^2

                  - y^2  - 2y

                    y^2 + y  

                           - y - 1

                             y + 1  

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