Math, asked by soumyasupare, 8 months ago

I am the greatest 5-digit number in which each digit is greater than
the one before it. Which number am I?
plz send answer and
please follow me then I will follow u​

Answers

Answered by badshah12534
1

Answer:

22222 or 00000 or 99999

is that correct so mark me as brianliest

Answered by Darika25
3

Answer:

The number cannot start with 9, because then there’s no way the second digit could be greater than the first. It cannot start with 8, because there is only one digit greater than 8, but 4 digits left in the number. the greatest digit you can place in the first position is 5. There are four digits greater than five, and four slots left to place them in.

The second digit must be six, because there are three digits greater than six, and three slots left.

The rest of the digits just fall into place after that: 56,789

=56,789

Step-by-step explanation:

Hope this answer will be helpful..

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