I am the smallest number, having four different prime factors. Can you find me?
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Answer:
The smallest four prime numbers are 2,3,5 and 7.
hence, the required number is 2\times3\times5\times7=2102×3×5×7=210
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Step-by-step explanation:
4 different prime factors are:
2,3,5,7
2*3*5*7 (multiple these all numbers then u will get)
hence the required number is 210
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