Math, asked by rakhi9647141788, 29 days ago


I am the smallest number, having four different prime factors. Can you find me?

Answers

Answered by vikashaakash6107
0

Answer:

The smallest four prime numbers are 2,3,5 and 7.

hence, the required number is 2\times3\times5\times7=2102×3×5×7=210

Answered by diyupurohit2008
0

Step-by-step explanation:

4 different prime factors are:

2,3,5,7

2*3*5*7 (multiple these all numbers then u will get)

hence the required number is 210

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