Question

i am thinking a two digit number.if i write three to the left of my number and double this three digit number the result is 27 times of my original number​

Answer 1

Answer:

let number be 10x+y

your condition (100x+10y+3)*2=27(10x+y)

==== 70x+7y=6

Answer 2

Answer:

Step-by-step explanation:

Let number which you thought be in form xy.

Now 3 is written on left of the number, so it becomes 3xy.

We can write this number like 3*100 + x*10 + y

On doubling the three digit number we get 27 times of x*10 + y

So,

2( 3*100 + x*10+ y ) = 27( x*10 + y )

600 + 20x + 2y = 270x + 27y

250x + 25y = 600

10x + y = 24

So, now we have to use hit and trial method, such that x,y remain single digit number

So, only case obtained is  

x = 2 then y= 4

So, our required answer is 24.

Thank you.

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