Question

I am three times as old as my son. Five years later, I shall be two and a half times as old as
my son. My present age is

Answer 1

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Let my age is x years and my son's age is y years. Then,

x = 3y..........(i)

Five years later, my age will be (x+5) years and my son's age will be (y+5) years.

∴x+5= (2+ 1/2) (y+5) [Given]

⇒2x−5y−15=0.........(ii)

Putting x=3y in equation (ii), we get

6y−5y−15=0⇒y=15

Putting y=15 in equation (i), we get

x=45

Hence, my present age is 45 years.

Additionally :

• The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS)

• A linear equation is an algebraic equation in which each term is either a constant or the product of a constant and a variable.

• Solving an equation means determining its root ie. to determine the value of the variable which satisfies it.

Answer 2

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Suppose my age is x years and my son's age is y years. Then,

x=3y ..(i)

Five years later, my age will be (x+5) years and my son's age will be (y+5) years.

∴x+5=(2+ 1/2)(y+5) [Given]

⇒2x−5y−15=0 .....(ii)

Putting x=3y in equation (ii), we get

6y−5y−15=0⇒y=15

Putting y=15 in equation (i), we get

x=45

Hence, my present age is 45 years and my son's present age is 15 years.