Question

I am trying to solve for 2001 to the power of 2.

Answer 1

Answer:

Step-by-step explanation:

(2001^2)

we will use identity for it ,

(2000+1)^2

we know,

(a+b)^2 = a^2 + 2ab + b^2

i.e.

(2000+1)^2 = (2000)^2 + 2(2000)(1) + (1)^2

that is,

4000000 + 4000 + 1

= 4004001

hope you understood

Answer 2

2001^2

(2000+1)^2

(a+b)^2 =a^2+b^2+2ab

= 2000^2+1^2+ 2*2000*1

=4000000+1+4000

=4004001

Therefore 4004001 is your answer.

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