Question

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Answer 1

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Answer 2

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$\huge\mathfrak{Answer}$----

Given , ∆ ABC and ∆ DBC are two isosceles triangles .

We have to prove that , Angle ABD = Angle ACD .

PROOF :

In ∆ ABC , AB = AC

We know that , if two sides of a triangle are equal , then their opposite angles are also equal .

So , Angle ABC = Angle ACB ......(1)

In ∆ DBC , BD = CD

Since we know that , if two sides of a triangle arw equal , then their opposite angles are also equal .

So , Angle DBC = Angle DCB .....(2)

Now , by adding the equations (1) & (2) , we get -----

Angle ABC + Angle DBC = Angle ACB + Angle DCB

=> Angle ABD = Angle ACD .

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