Question

(i) an = 4n - 3; a17, a24​

Answer 1

$</p><p></p><p></p><p>\bold{\underline{\sf Given:}} </p><p>\\ </p><p> \sf \rightarrow \quad a_{n} = 4n - 3</p><p></p><p>\\ \\</p><p></p><p>\bold{\underline{\sf To Find:}} </p><p>\\ </p><p> \sf \rightarrow \quad a_{17} \: , \; a_{24} </p><p></p><p>\\ \\</p><p></p><p>\bold{\underline{\sf Solution:}} </p><p>\\ \\</p><p>\sf \quad Put \quad n \: = 17 \\ \\</p><p> \sf \rightarrow \quad 4 \times 17 - 3</p><p>\\ \\</p><p> \sf \rightarrow \quad 68 - 3</p><p>\\ \\</p><p> \sf \rightarrow \quad 65</p><p>\\ \boxed{ \sf a_{17} = 65 }</p><p></p><p>\\ \\ \\ </p><p>\sf \quad Put \quad n \: = \: 24 </p><p></p><p>\\ \\ </p><p></p><p> \sf \rightarrow \quad 4 \times 24 - 3</p><p>\\ \\</p><p> \sf \rightarrow \quad 96 - 3</p><p></p><p>\\ \\</p><p></p><p> \sf \rightarrow \quad 93 </p><p></p><p>\\ </p><p>\boxed{ a_{24} = 93 }</p><p>$

Answer 2

$\huge\boxed{\boxed{\fcolorbox{white}{pink}{Answer}}}$

$\large\mathcal\orange{a_n= 4n-3}$

To find:

$a_{17}, a_{24}$

$\large\mathcal\green{Substituting\: the\: values}$

$a_{17}=4×17-3$

${\boxed{a_{17}= 65}}$

$a_{24}= 4×24-3$

${\boxed{a_{24}= 93}}$

Hope it helps úh