. i. An 8m high pole is 9m away from a building. If the distance between the top of the pole and the top of the building is 15m, then find the height of the building,
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Answered by
4
Answer:
The given scenario is shown in the attached figure.
Given:
DE=10
∠CDB=45
o
∠CDA=60
o
To find: AB
Solution:
tan∠CDB=
CD
CB
⇒tan45
o
=
CD
DE
∵CB=DE
1=
CD
10
CD=10 m
tan∠CDA=
CD
CA
⇒tan60
o
=
10
CA
3
=
10
CA
CA=10
3
m
AB=AC+BC
AB=10+10
3
≈27.32 m
Hence, the height of the tower is 27.32 m
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Answered by
1
The given scenerio is shown in the attached figure.
Given:
DE=10
<CDB=45
<CDA=60
To find AB
solution:
tan <CDB
CD
CA
tan 60
=10
CA
3
=
10
CA
CA=10
3
m
AB=AC+BC
AB=10+10
3
=27.32
therefore the height of the tower =27.32
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