Question

I an A.P the 4 term and 8 term are 13 and 36 respectly then the common different is

Answer 1

Step-by-step explanation:

Given;

4th term of AP=a+3d

13=a+3d.....eq1

8th term =a+7d

36=a+7d..... eq2

On sub eq 1 frm eq 2

a + 7d = 36

a + 3d = 13

4d=23

d=23/4

answer, d= 23/4

Answer 2

Answer:

Step-by-step explanation:

Let a be the first term and d be the common difference of the AP

ATQ,

13=a+(4-1)d

=>13=a+3d

=>13-3d=a.......(I)

Also,

36=a+7d..........(II)

Putting value of a from (I) in (II)

36=13-3d+7d

=>23=4d

=>d=23/4=5.75

Therefore, the common difference of the AP is 5.75

Hope it helps you...