Question

I an isosceles triangle find it's angle if it's base angle is 70 °

Answer 1

Answer:

the angles are 40°, 70° and 70°

Step-by-step explanation:

Given that angle C=70°

In an isosceles ∆ ABC , AB=AC

.: angle B = angle C

angle B = 70°

Now, again in ∆ ABC, by angle sum property,

angle A + angle B + angle C =180°

angle A + 70° +70° =180°

angle A = 180°-70°-70°

.: angle A = 40°

Here is your answer.

Hope it helps you.......

Gn

Answer 2

Answer:

In triangle ABC

let,

angle A be x

angle B be y

angle C be z

In an isosceles triangle 2 sides are equal.

therefore,

AB = AC.... 2 sides of isosceles triangle are equal

y = 70 ° ...... given

y = z = 70°.....base angles are equal (AB = AC)

therefore,

x + y + z = 180° .... sum of all angles of a triangle is 180°

x + 70 + 70 = 180

x = 180 - 140

x = 40°

therefore,

angle A = x = 40°

angle B = y = 70°

angle C = z = 70°

hope my answer will help you.

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