Question

(i) An object of mass 100 kg is accereated uniformly with a veolcity of 5 ms-1 to 8 ms-1 in 6 s . Calculate the intial and final momentum of the object. Also find the magnitude of force exerted on the object.

(ii) Two objects each of mass 1.5 kg are moving in the same straight line but in opposite direction. The velocity of each object is 2.5 ms-1 before collison during which they stuck together. Find the velocity of combination after collison.

Answer 1

The second question answer is in following topic

Answer 2

$\boxed{\huge{FIRST \: ANSWER \: (1)}}$

HELLO FRIEND HERE IS YOUR ANSWER,,,,,,,,


ANSWER :

Refer and consult to the following attachments for a detailed explanation and step by step solution with vital elaborations for certain formulas used into this query to arrive at a final conclusion that is,,,,


$\boxed{\bf{Initial \: Momentum = 500 \: Kg \: m/s}}$


$\boxed{\bf{Final \: Momentum = 800 \: Kg \: m/s}}$


$\boxed{\bf{Force = 50 \: N}}$


HOPE IT HELPS YOU AND CLEARS THE DOUBTS TO FIND THE INITAL AND FINAL MOMENTUMS AND FORCE EXERTED ON THE GIVEN OBJECT!!!!!!!


$\boxed{\huge{SECOND \: ANSWER \: (2)}}$


HELLO FRIEND HERE IS YOUR ANSWER,,,,,,,,

Given, let us consider,

Mass of the first object as variable "$m_1$" = 1.5 kg

Mass of the second object as variable "$m_2$" = 1.5 kg

Before colliding the velocity of first object that is "$m_1$", considered as variable "$v_1$" = 2.5 m/s

Before colliding and moving into an opposite direction the velocity of second object that is "$m_2$", considered as variable "$v_2$" = - 2.5 m/s

As, the second object is moving in a opposite direction it'll be taken as negative. And, after the collision has occurred, they're sticking together (as said in question).

Therefore, total mass of this newly formed combined object will be;

$m_1 v_1 + m_2 + v_2 = (m_1 + m_2) \times v$

$m_1 \: \: and \: \: m_2 = 1.5 \: kg$, $v_1 = 2.5 \: m/s\: \: and \: \: v_2 = - 2.5 \: m/s$

Now, Substituting the values given above into this equation :

$\bf{1.5 (2.5) + 1.5 (- 2.5) = (1.5 + 1.5) \times v}$

$\bf{3.75 - 3.75 = 3 \times v}$

Subtract the values and divided by "3".

$\bf{\frac{3.75 - 3.75}{3} = \frac{3}{3} \times v}$

$\therefore \: \: v = 0 \: m/s$

Therefore, the total combined object, after colliding should've a velocity of $\bf{0 \: m/s}$

HOPE THIS HELPS YOU AND CLEARS YOUR DOUBTS FOR FINDING VELOCITY AFTER THE COLLISION IS DONE!!!!!!!!