Question

I and
area
of
cross-
A wire of given material having length
area of cross-section A has a
cance of 4 ne what would be the
resistance of another wire of the same
material having length yz and area
of cross-section 2A?​

Answer 1

Resistance = p l/a [ p is constant]

For first wire length = l and area of croos section = a

Resistance = p l/a = 4 ohm [given]

For second wire length = l/2 and area of cross section = 2a

Resistance = p (l/2) / 2a

                   = p l/4a

                   = p l/a * 1/4 [p l/a = 4 ohm]

                   = 4*1/4 =  1 ohm

The resistance of second wire = 1 ohm

Hope it helps

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