Question

I and m are two parallel lines intersected by
another pair of parallel lines p and a
(see Fig. 7.19). Show that A ABC=ACDA.​

Answer 1

Answer:

Explanation:

check the pics given below

Answer 2

Explanation:

$\huge\color{Red}{\colorbox{black}{XxItzAdarshxX࿐ ❥︎}} </p><p>$

Solution:

It is given that p q and l m

To prove:

Triangles ABC and CDA are similar i.e. ΔABC ΔCDA

Proof:

Consider the ΔABC and ΔCDA,

(i) BCA = DAC and BAC = DCA Since they are alternate interior angles

(ii) AC = CA as it is the common arm

So, by ASA congruency criterion, triangle ABC triangle CDA.

$\huge\large\bf{\underline\green{❥thαnk \; чσu ♥♥}}$