Math, asked by akhaleshgujjar2465, 1 month ago

(i) anglePQR and anglePRQ
(ii) angleSQR and angleSRQ
(iii) angle x

Please give me solution...........​

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Answers

Answered by sheshi1999
0

Answer:

20 °

Step-by-step explanation:

SQR TRAINGLE IS ISOSCELES SO

70 +<SQR + <SRQ = 180

AS SQR AND SRQ ARE EQUAL

70 +2Y =180

Y = 55

NOW CONSIDERING BIGGER TRAINGLE

PQR

30+ <PQR + < PRQ = 180

<PQR = <PQS +<SQR

PQR =X + 55

now PQR is equal to PRQ

2(x+55) +30 = 180

2x + 110+30=180

2x = 180-140

2x= 40

x is 20

Answered by annunavneetsinghal
0

Step-by-step explanation:

i have done it roughly not confirm answer

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